Q.) How many five-digit numbers can be formed using the digits 2,3,8,7,5 exactly once such that the number is divisible by 125?
For a number to be divisible by 125 , the last three digits should be divisible by 125.
Let us take multiples of 125 : 125,250,375,500,625,750,875,1000,…….
Out of these multiples, the possible last three digits with given digits = 375,875
Now last three digits are fixed which can be filled in 2 ways. First 2 digits can be filled in 2! = 2 ways.
Hence , total number of numbers which are divisible by 125 = 2X2 = 4.
Hence , OPTION(C)