Home » Factors » Question on sum and no of factors

Question on sum and no of factors

Q.) Find the sum and no of factors of 1200 such that the factors are divisible by 15.

Solution:

1200 = { 2 }^{ 4 }*{ 5 }^{ 2 }*3

for the numbers to be divisible by 15, it should compulsorily have 3 and 5 in it.

sum of factors divisible by 15 = { (2 }^{ 0 }+{ 2 }^{ 1 }+{ 2 }^{ 2 }+{ 2 }^{ 3 }+{ 2 }^{ 4 })(5^{ 0 }+5^{ 1 })(3)

no of such factors = (4+1)*(2)*(1) Ans

facebooktwittergoogle_plusredditpinterestlinkedinmail

Leave a comment

Enter Email To Subscribe

Master Java Technologies

Connect With Me on Facebook

Search Questions Based on Topics